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Answer by C. A. for Eigenvectors for shear matrix and diagonalizing.

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0
0

If you evaluate this

$ \begin{pmatrix} 0 && 0 \\ 2 && 0 \end{pmatrix} \cdot \{x_1, x_2\}=0$

You get that $x_1 = 0$ and $x_2$ can be anything. Therefor any vector with $x_1 = 0$ is an eigenvector including $\{0, 1\}$ and any multiple of it (they all point in the same direction).


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